矩阵运算 - C语言实现(2)

InitialMatrixRand(&A, row, col); printf(\为：\\n\\n\PrintfMatrix(&A);

printf(\您要产生的矩阵B的行数和列数e.g:5,6: \ scanf(\ InitialMatrix(&B, row, col);

InitialMatrixRand(&B, row, col); printf(\为：\\n\\n\ PrintfMatrix(&B);

InitialMatrix(&C, A.row, A.col); InitialMatrixZero(&C, C.row, C.col); if (AddMatrix(&A, &B, &C) == 1) { printf(\矩阵的和为：A+B=\\n\\n\ PrintfMatrix(&C); }

else printf(\无法计算！\\n\\n\

DestroyMatrix(&A); DestroyMatrix(&B); DestroyMatrix(&C); }

if (inputevent == 7) { printf(\您要产生的矩阵A的行数和列数e.g:5,6: scanf(\ InitialMatrix(&A, row, col);

InitialMatrixRand(&A, row, col);

printf(\您要产生的矩阵B的行数和列数e.g:5,6: scanf(\ InitialMatrix(&B, row, col);

InitialMatrixRand(&B, row, col); InitialMatrix(&C, A.row, A.col); InitialMatrixZero(&C, C.row, C.col); if (MinusMatrix(&A, &B, &C) == 1) { printf(\矩阵的差为：A-B=\\n\\n\ PrintfMatrix(&C); }

else printf(\无法计算！\\n\\n\

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\\

}

DestroyMatrix(&A); DestroyMatrix(&B); DestroyMatrix(&C);

if (inputevent == 8) { printf(\您要产生的矩阵A的行数和列数e.g:5,6: \\n\ scanf(\ InitialMatrix(&A, row, col); InitialMatrixRand(&A, row, col); }

printf(\为：\\n\\n\PrintfMatrix(&A);

printf(\您要产生的矩阵B的行数和列数e.g:5,6: \\n\scanf(\InitialMatrix(&B, row, col);

InitialMatrixRand(&B, row, col); printf(\为：\\n\\n\PrintfMatrix(&B);

InitialMatrix(&C, A.row, A.col); InitialMatrixZero(&C, C.row, C.col); if (MultiMatrix(&A, &B, &C) == 1) { }

printf(\积为：A*B=\\n\\n\PrintfMatrix(&C);;

else printf(\无法计算；\\n\\n\DestroyMatrix(&A); DestroyMatrix(&B); DestroyMatrix(&C);

if (inputevent == 9) printf(\对不起，该函数尚在完善中\\n\\n\if (inputevent == 10) NMatrix(); if (inputevent == 0) break;

printf(\ 矩阵函数测试，请选择功能，输入对应的数字：\\n\

printf(\printf(\：输入一个矩阵，求矩阵均值；\\n\

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printf(\：产生一个随机数矩阵，求矩阵均值；\\n\ printf(\：输入两个个矩阵，求矩阵和；\\n\ printf(\：输入两个个矩阵，求矩阵差；\\n\ printf(\：输入两个矩阵，求矩阵积;\ printf(\：产生两个随机数矩阵，求矩阵和；\\n\ printf(\：产生两个随机数矩阵，求矩阵差；\\n\ printf(\：产生两个随机数矩阵，求矩阵积;\\n\ printf(\求矩阵的子阵,如矩阵的2-4行D,1-3列的子阵;\\n\ printf(\：输入一个方阵，求其逆矩阵\\n\ printf(\结束!\\n\ printf(\选择：\ scanf(\ } return 0; }

//其他函数

void InitialMatrix(Matrix *T, int row, int col) {

//printf(\分配内存中......\\n\int i;

int succ = 1;

//T=(Matrix *)malloc(sizeof(Matrix)); T->row = row; T->col = col;

T->mat = (double **)malloc(T->row * sizeof(double *)); if (T->mat == NULL) { succ = 0; } else { for (i = 0; i < T->row; i++) { T->mat[i] = (double *)malloc(T->col * sizeof(double)); if (T->mat[i] == NULL) { succ = 0; break;

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} } //if(succ==1) // printf(\内存分配成功|；?\\n\ //else printf(\内存分配失败；\\n\ } }

void InitialMatrixZero(Matrix *T, int row, int col) { //printf(\矩阵初始化为零中......\\n\ int i, j; for (i = 0; i < row; i++) for (j = 0; j < col; j++) T->mat[i][j] = 0; //printf(\矩阵初始化为零矩阵成功；\\n\}

void InitialMatrixRand(Matrix *T, int row, int col) { int i, j; for (i = 0; i < row; i++) for (j = 0; j < col; j++) (*T).mat[i][j] = rand() % 50; }

void InputMatrix(Matrix *T) { printf(\输入矩阵：\\n\ int i, j; for (i = 0; i < (*T).row; i++) for (j = 0; j < (*T).col; j++) scanf(\}

void DestroyMatrix(Matrix *T) { int i; for (i = 0; i < (*T).row; i++) free((*T).mat[i]); }

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void PrintfMatrix(Matrix *T) {

int i, j; for (i = 0; i < (*T).row; i++) { for (j = 0; j < (*T).col; j++) printf(\ \ printf(\ } }

int AddMatrix(Matrix *A, Matrix *B, Matrix *C) { int i, j; if ((*A).row == (*B).row && (*A).col == (*B).col) { for (i = 0; i < (*A).row; i++) for (j = 0; j < (*A).col; j++) (*C).mat[i][j] = (*A).mat[i][j] + (*B).mat[i][j]; for (i = 0; i < (*A).row; i++) for (j = 0; j < (*A).col; j++) return 1; } else { printf(\这两个矩阵不能相加！\\n\ return 0; } }

int MinusMatrix(Matrix *A, Matrix *B, Matrix *C) { int i, j; if ((*A).row == (*B).row && (*A).col == (*B).col) { for (i = 0; i < (*A).row; i++) for (j = 0; j < (*A).col; j++)

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