3.由低压加热器H7热平衡计算α低压加热器H7的抽汽系数αα7= =h7?hd,77
7
?c,5?hw,7?hw,8?/?h??d,5?hd,6?hd,7?
0.716??414.3?237.9?/1.0?0.0513??397.24?257.8?2851.0?257.8d,7
=0.04599 低压加热器H7的疏水系数αα
d,7
:
=α
d,6+
α7=0.0513-0.04599=0.09729
8
4.由低压加热器H8热平衡计算α
由于低加H8的进水焓hsg、疏水焓hd,8为未知,故先计算轴封加热器SG。由SG的热平衡,得轴封加热器出水焓hw,sg:
??h?h??? hw,sg=h′c+?sgsgd,sgc,5h
=137.3?0.0087455??3217.7?415??1.00.7167=171.49kJ/kg 表2-6.
由pw,sg=2.758Mpa, hw,sg=139.7℃,查得轴封加热器出水温度tw,sg=32.78℃.
低压加热器H8疏水温度td,8:
td,8=tw,sg+δt1=32.78+5.5=38.28℃
由p's=0.0197Mpa, td,8=38.28℃查得低压加热器H8疏水焓hd,8=160.27kJ/kg.
低压加热器H8的抽汽系数α8:
α8==
?c,5?hw,8?hw,sg?/?h??d,7?hd,7?hd,8?h8?hd,8
0.7167??237.9?139.7?/1.0?0.09729??257.8?160.27?2455.8?160.27d,8
=0.2653
低压加热器H8的疏水系数α
:
16
αd,8=αd,7+α8
=0.09729+0.02653=0.1238 (八)凝汽系数αc计算 1.小汽机抽汽系数αxj:
αxj=h?c,4??pu4?hc,xj?1.02157?26.4?0.03613
3169.0?2422.62.由凝汽器的质量平衡计算αc αc=αc,5-αd,8-Σαsg-αxj-αma
=0.7167-0.1238-0.008445-0.03613-0.0039263-0.03244=0.51658 3.由气轮机汽侧平衡校验αc H4抽汽口抽汽系数和α'4:
α'4=α4+αxj+αnf+αpl
=0.00714+0.03613+0.03235+0.01081 =0.08643
各加热器抽汽系数和Σαj:
Σαj=α1+α2+α3+α'4+α5+α6+α7+α8
=0.07089+0.07216+0.0856+0.08643+0.02553+0.02577+0.04599+0.02653=0.0659 轴封漏汽系数和Σαsg,k:
Σαsg,k=Σαsg,④+Σαsg,⑤+Σαsg,⑥+Σαsg,⑦+Σαsg,⑧+Σαsg,⑨+Σαsg,⑩+Σαsg,⒂=0.001429+0.001032+0.0015911+0.001264
+0.000673+0.0007626+0.0013694+0.0006244
=0.0087455 凝汽系数αc:
αc=1-Σαj-Σαsg=1-0.0659-0.0087455=0.51658
该值由凝汽器质量平衡计算得到的αc相等,凝汽系数计算正确。 (九)气轮机内功计算 1.凝汽流做工ωc
ωc=(αc–αsg,S+αsg,T)( h0–hc+qrh) –αJqrh-αsg,A(h0 –h2) =0.51658+(3397.2-2315.6+511.8)-(3397.2-3027.2)× 0. 01622=815.68kJ/kg
式中qrh—再热器吸热,qrh= hrh–h2=3538.9-3027.1=511.8 kJ/kg 2.抽汽流做功Σωa,j
1㎏H1抽汽做功ωa,1:
17
ωa,1= h0 –h1=3397.2-3144.2=253 kJ/kg 1㎏H2抽汽做功ωa,2:
ωa,2= h0 –h2=3397.2-3027.1=370.1 kJ/kg 1㎏H3抽汽做功ωa,3:
ωa,3= h0 –h3+ qrh=3397.2-3352.2+511.8
=566.8 kJ/kg
1㎏H4抽汽做功ωa,4:
ωa,4= h0 –h4+ qrh =3397.2-3169+511.8
=556.8 kJ/kg
1㎏H5抽汽做功ωa,5:
ωa,5= h0 –h5+ qrh =3397.2-2978.5+511.8
=930.5 kJ/kg
1㎏H6抽汽做功ωa,6:
ωa,6= h0 –h6+ qrh =3397.2-2851+511.8
=1058 kJ/kg
1㎏H7抽汽做功ωa,7:
ωa,7= h0 –h7+ qrh =3397.2-2716+511.8
=1193 kJ/kg
1㎏H8抽汽做功ωa,8:
ωa,8= h0 –h8+ qrh =3397.2-2455.8+511.8
=1453.2 kJ/kg
表2-9 做功量和抽汽量计算结果 1㎏抽汽做功(kJ/kg) 各级抽汽量(kJ/h) 144170 146753 174086 14520 51920 52409 93530 53454 H1 253 H2 370.1 H3 556.8 H4 740 H5 930.5 H6 1058 H7 1193 H8 1453.2 抽汽流总内功Σωa,j:
Σωa,j=α1ωa,1+α2ωa,2+α3ωa,3+α'4ωa,4+α5ωa,5+α6ωa,6+α7ω
a,7+α8ωa,8
=0.07089×253+0.07216
×370.1+0.0856×556.8+0.08643 ×740+0.02553×930.5+02577
×1.58+0.04599×1193+0.02653×1453.2
18
=273.4 kJ/kg
3.附加功量Σωsg,k
附加功量Σωsg,k是指各小汽流量作功之和:
Σωsg,k=α12(h0 –h12+ qrh)+( α8 + α9+, α10 ) (h0 –h8)
=0.03235(3397.2-3169+511.8)+(0.000673+0.0007626+ 0. 0013694)(3397.2-3169)=24.58 kJ/kg 4.气轮机内功ωi
ωi=ωc+Σωa,j+Σωsg,k=815.68+273.4+24.58
=1113.66 kJ/kg
(十)气轮机的内效率、热经济指标、汽水流量计算 气轮机比热耗q0:
q0= h0 –hfw+αrhqrh=3397.2-1204.4+0.8505×511.8 =1757.5 kJ/kg 气轮机绝对内效率ηi:
ηi=ωi /q0=1113.66/1757.5=0.63365
气轮机绝对电效率ηe:
ηe=ηmηgηi=0.985×0.99×0.63365=0.61791
气轮机热耗率q:
q=3600/ηe=3600/0.61791=5826.1 kJ/(kwh)
气轮机汽耗率d:
d=q/ q0=5826.1/1757.5=3.3149 kJ/(kwh)
气轮机进汽量D0:
D0=1000 d Pe=1000×3.3149×660=2033724㎏/h
式中Pe—气轮机额定功率,Pe=660MW
校验:气轮机进汽量D0=2033724㎏/h,与初选值相等。 给水流量Gfw:
Gfw=αc,4 D0=1.02157×2033724=2077591㎏/h
凝结水泵流量Gcp:
Gcp=αc,5 D0=0.7167×2033724=1457569㎏/h
凝汽量Dc:
Dc=αc D0=0.51658×2033724=1050581㎏/h
第一级抽汽量D1:
D1=α1 D0=0.07089×2033724=144170㎏/h
第二级抽汽量D2:
19
D2=α2 D0=0.07216×2033724=146753㎏/h
第三级抽汽量D3:
D3=α3 D0=0.0856×2033724=174086㎏/h
第四级抽汽量D4:
D4=α4D0=0.00714×2033724=14520㎏/h
第五级抽汽量D5:
D5=α5 D0=0.02553×2033724=51920㎏/h
第六级抽汽量D6:
D6=α6D0=0.02577×2033724=52409㎏/h
第七级抽汽量D7:
D7=α7 D0=0.04599×2033724=93530㎏/h
第八级抽汽量D8:
D8=α8D0=0.02653×2033724=53954㎏/h
(十一)全厂性热经济指标计算 1.锅炉参数计算 过热蒸汽参数:
由pb=17.42MPa,tb=541℃,查表得过热蒸汽出口比焓hb=3397.3 kJ/kg 再热蒸汽参数:
锅炉设计再热蒸汽出口压力pr=3.85 MPa,该压力以高于气轮机排汽压力p′rh=3.57 MPa,故按照气轮机侧参数,确定锅炉再热器出口压力pr=3.41 MPa.由pr=3.294 MPa和tr=541℃,查表得再热蒸汽出口比焓hr=3544 kJ/kg.
再热器换热量q′rh=hr–h2=3544-3027.1=516.9 kJ/kg 2.锅炉有效热量q1
q1=(αfW–αbl)( hb–hfw)+ αbl( hbl–hfw)+ αsp( hb–hsp)+ αrh qrh′ =(0.989-0.005408)×(3397.3-1204.41)+0.005408×(1760.3 -1204.41)+0.03257×(3397.3-890.4)+0.8505×516.9 =2681.1 kJ/kg 3.管道效率ηp
ηp= q0 /q1=1757.5/2681.1=0.6555
4.全厂效率ηcp
ηcp=ηbηpηe=0.925×0.6555×0.61791=0.37465 5.全厂发电标准煤耗bs
系数r= q1 /(q1–ηb qnf)=2681.1/(2681.1-0.925×79.81)
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