往复式压缩机习题解答(7)

CH4C2H6C3H8C4H10N2CO2ri85.00%5.40%5.60%1.90%1.60%0.50%ui

16.0430.0744.0958.1228.01644.01Ri[J/(kg*K)]518.772276.744188.79143.177296.75188.78pci(kPa)4628.744962.174246.283648.073282.027355Tci

190.65308.15369.95426.35126.05304.15mi=ri*ui/u(%)

69.9228.32812.6625.6332.2991.129

(1)

µ=∑µi*ri

=16.04*85.0%+30.07*5.4%+44.09*5.6%+58.12*1.9%+28.016*1.6%

+44.01*0.5%=19.499

R=

1=1

∑

ri

0.850.0540.0560.0190.0160.005=426.741

Ri

518.772+276.744+188.79+143.177+296.75+188.78(3)Tcm=∑Tci*ri=211.048

pcm=∑pci*ri=4598.779 ppp=46*105

r=779*103=1.0

cm4598.TTT=273+40r=

211.048

=1.483 cm查图4-2.2得：压缩性系数Z=0.875 （4）如表中所示

气体名称 质量分数/% CH4 69.92 C2H4

8.33

C3H6C4H10N2 2.30 CO2

1.13

【4-14】求75% H5

°

2及25% N2容积的混合气体的气体常数及在300*10Pa（绝），200C的比容。解：由已知条件及查附录三得：

H2

N2

ri

75%25%ui2.015628.016Ri

4121.74296.75

(2)

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