ANSYS结构非线性分析(1)

LESIZE,_Y1, , ,40,1, CMDEL,_Y CMDEL,_Y1 !*

CM,_Y,AREA

ASEL, , , , 1 CM,_Y1,AREA CHKMSH,\ CMSEL,S,_Y amesh,all CMDEL,_Y CMDEL,_Y1 CMDEL,_Y2 fini /solve

nlgeom,on! Turn on geometric nonlinearity

! Get the node numbers for the nodes located at the top ! of the axis of symmetry and at bottom right of the model ntop = node(0,thick,0) nright = node(radius,0,0)

! Activate the monitoring of the displacement and reaction force

histories

! during the analysis. This will be written out to the monitor

file ratch.mntr

monitor,1,ntop,uy monitor,2,nright,fy

outres,all,all ! Output all the results for

all sub-steps to the

! results file for

later postprocessing

! Select the nodes located at right end and constrain their radial

(x) and

! axial (y) direction displacement to be zero. nsel,s,loc,x,radius d,all,all

! Select the nodes located at left end and constrain their radial

(x) direction

! displacement to be zero. nsel,s,loc,x,0.0 d,all,ux,0.0

! Define the load for Load Step 1.

! Select the nodes located at top surface of plate and apply a

uniform pressure

! of 1.25 N/m^2 as dead load on the plate. nsel,s,loc,y,thick sf,all,pres,1.25 alls! Select all nodes

! Define the number of sub-steps (10). Also define maximum number

of

! substeps (50), and the minimum number of substeps (5) for the

automatic

! time stepping algorithm. nsub,10,50,5

! A load of: applied pressure (1.25) / number of sub-steps (10)

= 0.125 N/m^2

! will be applied for the first sub-step.

solve !

Solve load step 1

f = 0.0425 ! Define

the parameter, f, used to apply

!

the cyclic point load.

! Over six load steps apply a cyclic point load of magnitude f

= 0.0425 units

! applied at the center of the plate over three cycles ! Start Cycle 1 ! ---------------- nsel,s,node,,ntop

f,all,fy,-f ! Define

load for load step 2

nsel,all

nsubst,4,25,2 ! Set the

number of substeps, max and min number

! of

substeps

solve ! Solve

load step 2

nsel,s,node,,ntop

f,all,fy,f !

Define load for load step 3

nsel,all

nsubst,4,25,2 ! Set the

number of substeps, max and min number

!

of substeps

solve Solve load step 3

! Start Cycle 2 ! ---------------- nsel,s,node,,ntop

f,all,fy,-f load for load step 4

nsel,all

nsubst,4,25,2 number of substeps, max and min number

of substeps

solve Solve load step 4

nsel,s,node,,ntop

f,all,fy,f Define load for load step 5

nsel,all

nsubst,4,25,2 number of substeps, max and min number

of substeps

!

! Define

!

!

!

!

! Set the

! Set the

solve !

Solve load step 5

! Start Cycle 3 ! ---------------- nsel,s,node,,ntop

f,all,fy,-f ! Define

load for load step 6

nsel,all

nsubst,4,25,2 number of substeps, max and min number

of substeps

solve Solve load step 6

nsel,s,node,,ntop

f,all,fy,f Define load for load step 7

nsel,all

nsubst,4,25,2 number of substeps, max and min number

of sub-steps.

solve Solve load step 7

save fini /post1

!

!

!

!

!

! Set the

! Set the

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