
´óѧÎïÀíÊǸöÄÑÌâ°¡¡£¡£¡£¡£
7-3 ±¾½²Ö÷ÒªÄÚÈÝ
½éÖÊÖеľ²µç³¡
µç½éÖÊÖеĵ糡µÄÌØÐÔ¼°»ù±¾¹æÂÉ ´ÓÎïÖʽṹµÄ¹Ûµã¸øÓè½âÊÍ óÊÒ»½Ú µç½éÖʵļ«»¯ Êø¸¿µçºÉ Ò» µç½éÖÊ µçÈÝÆ÷ ºÏÉÏ¿ª¹Ø,²â³öÁ½¼«°åµçÊÆ²î ºÏÉÏ¿ª¹Ø ²â³öÁ½¼«°åµçÊÆ²î u 0 Õâʱ,¼«°åÉϵĵçºÉÁ¿Îª Õâʱ ¼«°åÉϵĵçºÉÁ¿Îª Q0 = C 0 u 0 ¶Ï¿ªµçÔ´,ÔÚÁ½¼«°å¼äÆüÈëµç½éÖÊ ¶Ï¿ªµçÔ´ ÔÚÁ½¼«°å¼äÆüÈëµç½éÖÊ ÔÚÁ½¼«°å¼ä ²â³öÁ½°å¼äµçÊÆ²î u =
u0
¦År
E=
E0
¦År
×¢:
¦Å
Õæ¿ÕÖÐ ¦Å r = 1 Ϊ½éÖʵÄÏà¶Ô½éµç³£Êý,ÊÇÎÞÁ¿¸ÙÁ¿ Ϊ½éÖʵÄÏà¶Ô½éµç³£Êý ÊÇÎÞÁ¿¸ÙÁ¿ ÆäËüµÄ ¦Å r >1 r
Q0 ¦Å r Q0 C= = = ¦Å r C0 u u0
{
°Ù¶ÈËÑË÷¡°77cn¡±»ò¡°Ãâ·Ñ·¶ÎÄÍø¡±¼´¿ÉÕÒµ½±¾Õ¾Ãâ·ÑÔĶÁÈ«²¿·¶ÎÄ¡£Êղر¾Õ¾·½±ãÏ´ÎÔĶÁ£¬Ãâ·Ñ·¶ÎÄÍø£¬Ìṩ¾µäС˵½ÌÓýÎÄ¿âµçÈÝÓëµç½éÖÊ1(5)ÔÚÏßÈ«ÎÄÔĶÁ¡£
Ïà¹ØÍÆ¼ö£º
